 | Daniel H. Whitney - 1835 - 614 pages
...its total weight, we find its specific gravity. The rule, therefore, is to divide the total weight by the loss of weight in water, and the quotient will be the specific gravity. If it baa liquid or a gas, we weigh it in wme. "vessel of known capacity, and then bv dividing that... | |
 | George Fownes - 1845 - 498 pages
...113-6 293*7 = 2-58, the specific gravity required. llo*o The arbitrary rule is generally thus written: "Divide the weight in air by the loss of weight in...water, and the quotient will be the specific gravity." In reality, it is not the weight in air which is required, but the weight the body would have in empty... | |
 | John Mitchell (F.C.S.) - 1846 - 450 pages
...certain amount, which will correspond to the weight of the bulk of water it has displaced. Divide its weight in air by the loss of weight in water, and the quotient will be the required specific gravity. This will be more readily understood by an example. Suppose we find the... | |
 | John Mitchell (F.C.S.) - 1846 - 448 pages
...certain amount, which will correspond to the weight of the bulk of water it has displaced. Divide its weight in air by the loss of weight in water, and the quotient will be the required specific gravity. This will be more readily understood by an example. Suppose we find the... | |
 | 1851 - 428 pages
...finding the specific gravity of a mass of solid matter, and also state how the substance is weighed in water : — " Divide the weight in air by the loss...water, and the quotient will be the specific gravity." 4. If a capillary tube of glass be successively plunged in two vessels, one of water and another of... | |
 | George Fownes - 1853 - 132 pages
...weight of an equal bulk of water, which is all we require to know. Hence the rule given in books:— " Divide the weight in air by the loss of weight in...and the quotient will be the specific gravity." The same principle guides all these operations, although the method has often to be altered to meet particular... | |
 | John Mitchell (analytical chemist.) - 1854 - 608 pages
...certain amount, which will correspond to the weight of the bulk of water it has displaced. Divide its weight in air by the loss of weight in water, and the quotient will be the required specific gravity. This will be more readily understood by an example. Suppose we find the... | |
 | George Fownes - 1857 - 576 pages
...293-7 TjjjTTj = 2-68, the specific gravity required. The arbitrary rule is generally thus written : "Divide the weight in air by the loss of weight in...water, and the quotient will be the specific gravity. " In reality, it is not the weight in air which is required, but the weight the body would have in... | |
 | Elias Loomis - 1858 - 374 pages
...difference between these two weights is the weight of a quantity of water equal in volume to the solid. Then divide the weight in air by the loss of weight in water, the quotient will express the specific gravity of the body. Example. If a piece of marble weighs 1967£... | |
 | John Blenkarn - 1859 - 300 pages
...temperature of 60° Fahrenheit, by plunging the substance therein, and suspending it by a fine thread. Next, divide the weight in air by the loss of weight in...water, and the quotient will be the specific gravity. Water I'OOO Oak -925 Ash -800 Beech -852 Elm , -600 Fir -550 Maple -755 Mahogany T063 Platinum 21-500... | |
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Divide the weight in air by the loss of weight in water, and the quotient will be the specific gravity. 
